What is the answer to (3x^2)/(x+1)-1=0 ?

The answer to (3x^2)/(x+1)-1=0 is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6

Solve for x: (3x^2)/(x+1)-1=0

The solution is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6

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\frac{3 x ^{2}}{x + 1} - 1 = 0

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

Decimal Notation

x = 0.76759 \dots, x = - 0.43425 \dots

Solution steps

\frac{3 x ^{2}}{x + 1} - 1 = 0

Multiply both sides by

x + 1

3 x^{2} - (x + 1) = 0

Solve

3 x^{2} - (x + 1) = 0 : x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

5 x - 3 = \frac{2}{x}

\frac{8}{3 x - 4} = \frac{3}{x + 4}

\frac{3}{x + 5} + \frac{4}{x} = 2

\frac{4}{3} = \frac{84 - x}{x}

\frac{x + 2}{x + 6} = \frac{1}{3}

What is the answer to (3x^2)/(x+1)-1=0 ?
The answer to (3x^2)/(x+1)-1=0 is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6
Solve for x: (3x^2)/(x+1)-1=0
The solution is x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6