What is the answer to x^{-2}+3x^{-1}-18=0 ?

The answer to x^{-2}+3x^{-1}-18=0 is x=-1/6 ,x= 1/3

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x^{-2}+3x^{-1}-18=0

x^{- 2} + 3 x^{- 1} - 18 = 0

x = - \frac{1}{6}, x = \frac{1}{3}

Solution steps

x^{- 2} + 3 x^{- 1} - 18 = 0

Refine

\frac{1}{x ^{2}} + \frac{3}{x} - 18 = 0

Multiply by LCM

1 + 3 x - 18 x^{2} = 0

Solve

1 + 3 x - 18 x^{2} = 0 : x = - \frac{1}{6}, x = \frac{1}{3}

x = - \frac{1}{6}, x = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{6}, x = \frac{1}{3}

\frac{3}{x} + \frac{3}{2 x} = 2

\frac{28}{b} + 9 = 16

\frac{π}{2} = \frac{2 π}{b}

5 = \frac{x ^{2} - 4}{x + 16}

\frac{8}{5 x - 4} = \frac{6}{x + 5}

What is the answer to x^{-2}+3x^{-1}-18=0 ?
The answer to x^{-2}+3x^{-1}-18=0 is x=-1/6 ,x= 1/3
Solve for x: x^{-2}+3x^{-1}-18=0
The solution is x=-1/6 ,x= 1/3