What is the answer to x^{-2}-7x^{-1}+10=0 ?

The answer to x^{-2}-7x^{-1}+10=0 is x= 1/2 ,x= 1/5

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x^{-2}-7x^{-1}+10=0

x^{- 2} - 7 x^{- 1} + 10 = 0

x = \frac{1}{2}, x = \frac{1}{5}

Solution steps

x^{- 2} - 7 x^{- 1} + 10 = 0

Refine

\frac{1}{x ^{2}} - \frac{7}{x} + 10 = 0

Multiply by LCM

1 - 7 x + 10 x^{2} = 0

Solve

1 - 7 x + 10 x^{2} = 0 : x = \frac{1}{2}, x = \frac{1}{5}

x = \frac{1}{2}, x = \frac{1}{5}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = \frac{1}{5}

\frac{2}{t} - 1 = 5 - \frac{1}{t}

\frac{3}{x + 3} = 12

\frac{2}{x} = \frac{8}{12}

\frac{3}{4} = \frac{5}{x}

\frac{1}{10} = \frac{10}{k}

What is the answer to x^{-2}-7x^{-1}+10=0 ?
The answer to x^{-2}-7x^{-1}+10=0 is x= 1/2 ,x= 1/5
Solve for x: x^{-2}-7x^{-1}+10=0
The solution is x= 1/2 ,x= 1/5