What is the answer to 5x^{-2}-19x^{-1}-4=0 ?

The answer to 5x^{-2}-19x^{-1}-4=0 is x=-5,x= 1/4

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5x^{-2}-19x^{-1}-4=0

5 x^{- 2} - 19 x^{- 1} - 4 = 0

x = - 5, x = \frac{1}{4}

Decimal Notation

x = - 5, x = 0.25

Solution steps

5 x^{- 2} - 19 x^{- 1} - 4 = 0

Refine

\frac{5}{x ^{2}} - \frac{19}{x} - 4 = 0

Multiply by LCM

5 - 19 x - 4 x^{2} = 0

Solve

5 - 19 x - 4 x^{2} = 0 : x = - 5, x = \frac{1}{4}

x = - 5, x = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 5, x = \frac{1}{4}

\frac{x}{x + 6} = \frac{9}{8}

- \frac{7}{x + 7} + 6 = \frac{x}{x + 7}

\frac{k p}{1 + k p} = 0.99

4 x = \frac{4}{x}

\frac{1}{x + 2} = \frac{5}{x}

What is the answer to 5x^{-2}-19x^{-1}-4=0 ?
The answer to 5x^{-2}-19x^{-1}-4=0 is x=-5,x= 1/4
Solve for x: 5x^{-2}-19x^{-1}-4=0
The solution is x=-5,x= 1/4