What is the answer to (-2x^2+5x-1)/(2x-1)=0 ?

The answer to (-2x^2+5x-1)/(2x-1)=0 is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4

Solve for x: (-2x^2+5x-1)/(2x-1)=0

The solution is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4

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\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1} = 0

x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

Decimal Notation

x = 0.21922 \dots, x = 2.28077 \dots

Solution steps

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 5 x - 1 = 0

Solve

- 2 x^{2} + 5 x - 1 = 0 : x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{2}

Combine undefined points with solutions:

x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

\frac{5 x}{x + 2} = \frac{3 x}{x + 1}

\frac{34}{x} = \frac{17}{2}

\frac{2 x}{x + 3} = 9 - \frac{6}{x + 3}

\frac{3}{4 x} - \frac{1}{2 x} = 4

\frac{2}{3} = \frac{5}{x}

What is the answer to (-2x^2+5x-1)/(2x-1)=0 ?
The answer to (-2x^2+5x-1)/(2x-1)=0 is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4
Solve for x: (-2x^2+5x-1)/(2x-1)=0
The solution is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4