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What is the answer to 4x^{-4}-7x^{-2}-2=0 ?
The answer to 4x^{-4}-7x^{-2}-2=0 is x=2i,x=-2i,x= 1/(sqrt(2)),x=-1/(sqrt(2))Solve for x: 4x^{-4}-7x^{-2}-2=0
The solution is x=2i,x=-2i,x= 1/(sqrt(2)),x=-1/(sqrt(2))