What is the answer to 6z-4/(1+2z)=3 ?

The answer to 6z-4/(1+2z)=3 is z=(sqrt(7))/(2sqrt(3)),z=-(sqrt(7))/(2sqrt(3))

Solve for z: 6z-4/(1+2z)=3

The solution is z=(sqrt(7))/(2sqrt(3)),z=-(sqrt(7))/(2sqrt(3))

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6 z - \frac{4}{1 + 2 z} = 3

z = \frac{7}{2 3}, z = - \frac{7}{2 3}

Decimal Notation

z = 0.76376 \dots, z = - 0.76376 \dots

Solution steps

6 z - \frac{4}{1 + 2 z} = 3

Multiply both sides by

1 + 2 z

6 z (1 + 2 z) - 4 = 3 (1 + 2 z)

Solve

6 z (1 + 2 z) - 4 = 3 (1 + 2 z) : z = \frac{7}{2 3}, z = - \frac{7}{2 3}

z = \frac{7}{2 3}, z = - \frac{7}{2 3}

Verify Solutions

Find undefined (singularity) points:

z = - \frac{1}{2}

Combine undefined points with solutions:

z = \frac{7}{2 3}, z = - \frac{7}{2 3}

10 = 500 (b)^{- 3}

\frac{x}{x - 4} = \frac{4}{x - 4} + 5

\frac{1}{x - 3} = \frac{1}{2 x + 1}

\frac{9 x - 1}{x - 1} = 0

- \frac{24}{( x - 3 ) ^{2}} = - 6

What is the answer to 6z-4/(1+2z)=3 ?
The answer to 6z-4/(1+2z)=3 is z=(sqrt(7))/(2sqrt(3)),z=-(sqrt(7))/(2sqrt(3))
Solve for z: 6z-4/(1+2z)=3
The solution is z=(sqrt(7))/(2sqrt(3)),z=-(sqrt(7))/(2sqrt(3))