What is the answer to 1/(x^2)+4x^2-4=0 ?

The answer to 1/(x^2)+4x^2-4=0 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: 1/(x^2)+4x^2-4=0

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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\frac{1}{x ^{2}} + 4 x^{2} - 4 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

\frac{1}{x ^{2}} + 4 x^{2} - 4 = 0

Multiply both sides by

x^{2}

1 + 4 x^{4} - 4 x^{2} = 0

Solve

1 + 4 x^{4} - 4 x^{2} = 0 : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{x}{x - 3} + 5 = \frac{3}{x - 3}

\frac{x - 9}{x - 6} = \frac{- 4}{x}

6 - \frac{2}{x} = 10

\frac{5}{x} - 2 = \frac{x}{3}

\frac{2}{x + 4} = \frac{3}{x}

What is the answer to 1/(x^2)+4x^2-4=0 ?
The answer to 1/(x^2)+4x^2-4=0 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: 1/(x^2)+4x^2-4=0
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))