What are the solutions to the equation 4^2+x^2=10^2 ?

The solutions to the equation 4^2+x^2=10^2 are x=2sqrt(21),x=-2sqrt(21)

Find the zeros of 4^2+x^2=10^2

The zeros of 4^2+x^2=10^2 are x=2sqrt(21),x=-2sqrt(21)

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4^{2} + x^{2} = 1 0^{2}

x = 221, x = - 221

Decimal Notation

x = 9.16515 \dots, x = - 9.16515 \dots

Solution steps

4^{2} + x^{2} = 1 0^{2}

Move

4^{2}

to the right side

x^{2} = 84

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 84, x = - 84

84 = 221

- 84 = - 221

x = 221, x = - 221

x^{3} + 8 x^{2} + 9 x + 72

- 3 v \geq - 6

x (x - 7) = 0

25 a^{2} - 30 ab + 9 b^{2}

y^{2} - y - 6 = 0

What are the solutions to the equation 4^2+x^2=10^2 ?
The solutions to the equation 4^2+x^2=10^2 are x=2sqrt(21),x=-2sqrt(21)
Find the zeros of 4^2+x^2=10^2
The zeros of 4^2+x^2=10^2 are x=2sqrt(21),x=-2sqrt(21)