What is the answer to R^3=5+H/a ?

The answer to R^3=5+H/a is a= H/(R^3-5);\quad \ne True for all R

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R^3=5+H/a

R^{3} = 5 + \frac{H}{a}

a = \frac{H}{R ^{3} - 5}; \neq = True for all R

Solution steps

R^{3} = 5 + \frac{H}{a}

Move

5

to the left side

R^{3} - 5 = \frac{H}{a}

Multiply both sides by

a

R^{3} a - 5 a = H

Factor

R^{3} a - 5 a : a (R^{3} - 5)

a (R^{3} - 5) = H

Divide both sides by

R^{3} - 5; \neq =

True for all

R

a = \frac{H}{R ^{3} - 5}; \neq = True for all R

37.5 = \frac{150 x}{200 - x}

\frac{x}{x - 2} = 2

\frac{x + 2}{x - 6} = 2

7 + \frac{6}{x} = 1

\frac{x \frac{3}{2}}{x - 6} = x - 8

What is the answer to R^3=5+H/a ?
The answer to R^3=5+H/a is a= H/(R^3-5);\quad \ne True for all R