What is the answer to 1+((x+3)2x)/(x^2)=0 ?

The answer to 1+((x+3)2x)/(x^2)=0 is x=-2

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1+((x+3)2x)/(x^2)=0

1 + \frac{( x + 3 ) 2 x}{x ^{2}} = 0

x = - 2

Solution steps

1 + \frac{( x + 3 ) \cdot 2 x}{x ^{2}} = 0

Simplify

\frac{( x + 3 ) \cdot 2 x}{x ^{2}} : \frac{2 ( x + 3 )}{x}

1 + \frac{2 ( x + 3 )}{x} = 0

Multiply both sides by

x

x + 2 (x + 3) = 0

Expand

2 (x + 3) : 2 x + 6

x + 2 x + 6 = 0

Add similar elements:

x + 2 x = 3 x

3 x + 6 = 0

Move

6

to the right side

3 x = - 6

Divide both sides by

3

x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 2

(x + 5)^{- 3} = - 1

\frac{2}{x - 1} = \frac{3}{x + 2}

\frac{1 - 3 x}{2 x + 3} = \frac{2}{7}

\frac{7}{2 a} - \frac{2}{3 a} = 1

\frac{4}{u + 4} = \frac{8}{2 u + 8} - 3

What is the answer to 1+((x+3)2x)/(x^2)=0 ?
The answer to 1+((x+3)2x)/(x^2)=0 is x=-2
Solve for x: 1+((x+3)2x)/(x^2)=0
The solution is x=-2