What is the answer to solvefor u,y= 1/u+x ?

The answer to solvefor u,y= 1/u+x is u= 1/(y-x);\quad y\ne x

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solvefor u,y= 1/u+x

solve for

u, y = \frac{1}{u} + x

u = \frac{1}{y - x}; y \neq = x

Solution steps

y = \frac{1}{u} + x

Move

x

to the left side

y - x = \frac{1}{u}

Multiply both sides by

u

y u - xu = 1

Factor

y u - xu : u (y - x)

u (y - x) = 1

Divide both sides by

y - x; y \neq = x

u = \frac{1}{y - x}; y \neq = x

n, A = P (b + \frac{x}{n})

3 x^{- 2} - 17 x^{- 1} - 6 = 0

x, y^{2} = \frac{1}{x}

f, w = \frac{r}{f}

x, y = \frac{x}{1 - x}

What is the answer to solvefor u,y= 1/u+x ?
The answer to solvefor u,y= 1/u+x is u= 1/(y-x);\quad y\ne x