What is the answer to 5x^{-2}-29x^{-1}+20=0 ?

The answer to 5x^{-2}-29x^{-1}+20=0 is x= 5/4 ,x= 1/5

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5x^{-2}-29x^{-1}+20=0

5 x^{- 2} - 29 x^{- 1} + 20 = 0

x = \frac{5}{4}, x = \frac{1}{5}

Decimal Notation

x = 1.25, x = 0.2

Solution steps

5 x^{- 2} - 29 x^{- 1} + 20 = 0

Refine

\frac{5}{x ^{2}} - \frac{29}{x} + 20 = 0

Multiply by LCM

5 - 29 x + 20 x^{2} = 0

Solve

5 - 29 x + 20 x^{2} = 0 : x = \frac{5}{4}, x = \frac{1}{5}

x = \frac{5}{4}, x = \frac{1}{5}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{5}{4}, x = \frac{1}{5}

\frac{2 x - 3}{4 - 5 x} = - \frac{2}{3}

\frac{8}{x + 3} = \frac{11}{x + 4}

\frac{25}{8} = \frac{200}{b}

\frac{2 k}{2 x + h} = \frac{k}{x + h}

\frac{4}{6} = \frac{24}{a}

What is the answer to 5x^{-2}-29x^{-1}+20=0 ?
The answer to 5x^{-2}-29x^{-1}+20=0 is x= 5/4 ,x= 1/5
Solve for x: 5x^{-2}-29x^{-1}+20=0
The solution is x= 5/4 ,x= 1/5