What is the answer to 1/(x^2)=9^{-1} ?

The answer to 1/(x^2)=9^{-1} is x=3,x=-3

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1/(x^2)=9^{-1}

\frac{1}{x ^{2}} = 9^{- 1}

x = 3, x = - 3

Solution steps

\frac{1}{x ^{2}} = 9^{- 1}

Refine

\frac{1}{x ^{2}} = \frac{1}{9}

Cross multiply

9 = x^{2}

Solve

9 = x^{2} : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 3, x = - 3

\frac{3 x}{x + 2} = 5 - \frac{6}{x + 2}

\frac{x - 4}{4 x} + 1 = \frac{x + 4}{x}

x, 1 - \frac{4}{x} = - 3 x

\frac{190}{90} = \frac{80 + x}{x}

50 = \frac{100 x}{1 + x}