What is the answer to x^2+1/x =0,x>0 ?

The answer to x^2+1/x =0,x>0 is x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

Solve for x: x^2+1/x =0,x>0

The solution is x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

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x^{2} + \frac{1}{x} = 0, x > 0

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

Solution steps

x^{2} + \frac{1}{x} = 0

Multiply both sides by

x

x^{3} + 1 = 0

Solve

x^{3} + 1 = 0 : x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

Check constrains

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

r, S = \frac{a}{a - r}

\frac{3 x + 5}{2} + \frac{1}{x} = 0

\frac{8}{u} - (- 2) = 6

\frac{0.1}{2} = \frac{0.5}{x}

\frac{1}{5 x} = \frac{2}{5}

What is the answer to x^2+1/x =0,x>0 ?
The answer to x^2+1/x =0,x>0 is x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i
Solve for x: x^2+1/x =0,x>0
The solution is x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i