What is the answer to 8x^{-4}-6x^{-2}+1=0 ?

The answer to 8x^{-4}-6x^{-2}+1=0 is x=2,x=-2,x=sqrt(2),x=-sqrt(2)

Solve for x: 8x^{-4}-6x^{-2}+1=0

The solution is x=2,x=-2,x=sqrt(2),x=-sqrt(2)

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8 x^{- 4} - 6 x^{- 2} + 1 = 0

x = 2, x = - 2, x = 2, x = - 2

Decimal Notation

x = 2, x = - 2, x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

8 x^{- 4} - 6 x^{- 2} + 1 = 0

Refine

\frac{8}{x ^{4}} - \frac{6}{x ^{2}} + 1 = 0

Multiply by LCM

8 - 6 x^{2} + x^{4} = 0

Solve

8 - 6 x^{2} + x^{4} = 0 : x = 2, x = - 2, x = 2, x = - 2

x = 2, x = - 2, x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 2, x = - 2, x = 2, x = - 2

\frac{3}{4 n - 1} = \frac{2}{2 n - 5}

\frac{x}{2 a} = \frac{4 a}{x + 2 a}

\frac{1}{x - 2} + 5 = \frac{21}{x - 2}

\frac{x ^{2}}{x ^{2} - 1} = 0

\frac{4 ( x - 2 )}{x - 3} = 3

What is the answer to 8x^{-4}-6x^{-2}+1=0 ?
The answer to 8x^{-4}-6x^{-2}+1=0 is x=2,x=-2,x=sqrt(2),x=-sqrt(2)
Solve for x: 8x^{-4}-6x^{-2}+1=0
The solution is x=2,x=-2,x=sqrt(2),x=-sqrt(2)