What is the answer to 64x^{-4}-20x^{-2}+1=0 ?

The answer to 64x^{-4}-20x^{-2}+1=0 is x=4,x=-4,x=2,x=-2

Solve for x: 64x^{-4}-20x^{-2}+1=0

The solution is x=4,x=-4,x=2,x=-2

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64 x^{- 4} - 20 x^{- 2} + 1 = 0

x = 4, x = - 4, x = 2, x = - 2

Solution steps

64 x^{- 4} - 20 x^{- 2} + 1 = 0

Refine

\frac{64}{x ^{4}} - \frac{20}{x ^{2}} + 1 = 0

Multiply by LCM

64 - 20 x^{2} + x^{4} = 0

Solve

64 - 20 x^{2} + x^{4} = 0 : x = 4, x = - 4, x = 2, x = - 2

x = 4, x = - 4, x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 4, x = - 4, x = 2, x = - 2

\frac{3}{6} = \frac{9}{n}

x^{2} - \frac{1}{x ^{2}} = 0

\frac{3}{x - 1} - \frac{1}{x} = 0

\frac{7}{3} = \frac{21}{x}

0.15 = \frac{75}{75 + x}

What is the answer to 64x^{-4}-20x^{-2}+1=0 ?
The answer to 64x^{-4}-20x^{-2}+1=0 is x=4,x=-4,x=2,x=-2
Solve for x: 64x^{-4}-20x^{-2}+1=0
The solution is x=4,x=-4,x=2,x=-2