What is the answer to 1/(y-3)=(-1)/(3-y) ?

The answer to 1/(y-3)=(-1)/(3-y) is y\ne 3

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1/(y-3)=(-1)/(3-y)

\frac{1}{y - 3} = \frac{- 1}{3 - y}

y \neq = 3

Solution steps

\frac{1}{y - 3} = \frac{- 1}{3 - y}

Cross multiply

3 - y = - (y - 3)

Solve

3 - y = - (y - 3) :

True for all

y

y \neq = 3

Verify Solutions

Find undefined (singularity) points:

y = 3

Since the equation is undefined for:

3

y \neq = 3

\frac{x ^{2} - 1}{x + 1} = - 2

\frac{2 x}{x + 1} = \frac{2 x + 1}{x}

\frac{8 h}{3 j} = 6 k

\frac{n !}{( n - 2 ) !} = 20

\frac{x ^{2} - 2 x - 3}{( x - 3 ) ^{2}} = 0

What is the answer to 1/(y-3)=(-1)/(3-y) ?
The answer to 1/(y-3)=(-1)/(3-y) is y\ne 3
Solve for y: 1/(y-3)=(-1)/(3-y)
The solution is y\ne 3