What is the answer to 4/z =(3z)/(z-3) ?

The answer to 4/z =(3z)/(z-3) is z= 2/3+i(4sqrt(2))/3 ,z= 2/3-i(4sqrt(2))/3

Solve for z: 4/z =(3z)/(z-3)

The solution is z= 2/3+i(4sqrt(2))/3 ,z= 2/3-i(4sqrt(2))/3

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\frac{4}{z} = \frac{3 z}{z - 3}

z = \frac{2}{3} + i \frac{4 2}{3}, z = \frac{2}{3} - i \frac{4 2}{3}

Solution steps

\frac{4}{z} = \frac{3 z}{z - 3}

Cross multiply

4 (z - 3) = 3 z^{2}

Solve

4 (z - 3) = 3 z^{2} : z = \frac{2}{3} + i \frac{4 2}{3}, z = \frac{2}{3} - i \frac{4 2}{3}

z = \frac{2}{3} + i \frac{4 2}{3}, z = \frac{2}{3} - i \frac{4 2}{3}

\frac{x}{x + 1} = \frac{4}{3}

x + \frac{1}{x} = - 4

\frac{1}{8} = \frac{1}{1 - 6 x}

I = \frac{PN}{RN + A}, N

\frac{- 2}{x} = \frac{7}{x - 9} - 1

What is the answer to 4/z =(3z)/(z-3) ?
The answer to 4/z =(3z)/(z-3) is z= 2/3+i(4sqrt(2))/3 ,z= 2/3-i(4sqrt(2))/3
Solve for z: 4/z =(3z)/(z-3)
The solution is z= 2/3+i(4sqrt(2))/3 ,z= 2/3-i(4sqrt(2))/3