What is the answer to 7/(x+1)-4/(3x-2)=1 ?

The answer to 7/(x+1)-4/(3x-2)=1 is x=4,x= 4/3

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7/(x+1)-4/(3x-2)=1

\frac{7}{x + 1} - \frac{4}{3 x - 2} = 1

x = 4, x = \frac{4}{3}

Solution steps

\frac{7}{x + 1} - \frac{4}{3 x - 2} = 1

Multiply by LCM

7 (3 x - 2) - 4 (x + 1) = (x + 1) (3 x - 2)

Solve

7 (3 x - 2) - 4 (x + 1) = (x + 1) (3 x - 2) : x = 4, x = \frac{4}{3}

x = 4, x = \frac{4}{3}

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = \frac{2}{3}

Combine undefined points with solutions:

x = 4, x = \frac{4}{3}

y, x = \frac{4}{y}

x, g = \frac{( x - c )}{x}

\frac{m}{n} = \frac{8 m}{x n}

3 - \frac{3}{3 - \frac{1}{x}} = 1

x^{- 2} = 16

What is the answer to 7/(x+1)-4/(3x-2)=1 ?
The answer to 7/(x+1)-4/(3x-2)=1 is x=4,x= 4/3
Solve for x: 7/(x+1)-4/(3x-2)=1
The solution is x=4,x= 4/3