What is the answer to 3y^{-2}+y^{-1}-4=0 ?

The answer to 3y^{-2}+y^{-1}-4=0 is y=-3/4 ,y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3y^{-2}+y^{-1}-4=0

3 y^{- 2} + y^{- 1} - 4 = 0

y = - \frac{3}{4}, y = 1

Solution steps

3 y^{- 2} + y^{- 1} - 4 = 0

Refine

\frac{3}{y ^{2}} + \frac{1}{y} - 4 = 0

Multiply by LCM

3 + y - 4 y^{2} = 0

Solve

3 + y - 4 y^{2} = 0 : y = - \frac{3}{4}, y = 1

y = - \frac{3}{4}, y = 1

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = - \frac{3}{4}, y = 1

f (x) (f (x) (x)^{- 1} (x)) = x

\frac{4}{x} + \frac{1}{2 x} = 7

a = \frac{3}{x + 2}

r, L = \frac{E}{r + r}

\frac{1}{x} - \frac{2}{x - 2} = 3

What is the answer to 3y^{-2}+y^{-1}-4=0 ?
The answer to 3y^{-2}+y^{-1}-4=0 is y=-3/4 ,y=1
Solve for y: 3y^{-2}+y^{-1}-4=0
The solution is y=-3/4 ,y=1