What is the answer to (18x^2)/(x^4+81)=1 ?

The answer to (18x^2)/(x^4+81)=1 is x=3,x=-3

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(18x^2)/(x^4+81)=1

\frac{18 x ^{2}}{x ^{4} + 81} = 1

x = 3, x = - 3

Solution steps

\frac{18 x ^{2}}{x ^{4} + 81} = 1

Multiply both sides by

x^{4} + 81

18 x^{2} = x^{4} + 81

Solve

18 x^{2} = x^{4} + 81 : x = 3, x = - 3

x = 3, x = - 3

x^{- 3} = \frac{1}{27}

1 + \frac{1}{x} = x

7 - \frac{2}{x - 4} = 5

3 + \frac{x - 2}{x - 4} = 2

\frac{x}{x - 3} + 2 = \frac{3}{x - 3}

What is the answer to (18x^2)/(x^4+81)=1 ?
The answer to (18x^2)/(x^4+81)=1 is x=3,x=-3
Solve for x: (18x^2)/(x^4+81)=1
The solution is x=3,x=-3