What is the answer to 2+1/(b-2)=(3b)/(b+2) ?

The answer to 2+1/(b-2)=(3b)/(b+2) is b=1,b=6

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2+1/(b-2)=(3b)/(b+2)

2 + \frac{1}{b - 2} = \frac{3 b}{b + 2}

b = 1, b = 6

Solution steps

2 + \frac{1}{b - 2} = \frac{3 b}{b + 2}

Multiply by LCM

2 (b - 2) (b + 2) + b + 2 = 3 b (b - 2)

Solve

2 (b - 2) (b + 2) + b + 2 = 3 b (b - 2) : b = 1, b = 6

b = 1, b = 6

Verify Solutions

Find undefined (singularity) points:

b = 2, b = - 2

Combine undefined points with solutions:

b = 1, b = 6

\frac{x + 1}{x} = 0

\frac{1}{x - 2} = 1

\frac{2}{x + 2} = \frac{x - 4}{8}

\frac{9}{x} - \frac{x}{3} = 2

\frac{( y + 2 ) ( y + 3 )}{( y + 2 )} = 1

What is the answer to 2+1/(b-2)=(3b)/(b+2) ?
The answer to 2+1/(b-2)=(3b)/(b+2) is b=1,b=6
Solve for b: 2+1/(b-2)=(3b)/(b+2)
The solution is b=1,b=6