What is the answer to (y-1)(y-2)= 1/(2y^2) ?

The answer to (y-1)(y-2)= 1/(2y^2) is y\approx 2.10257…,y\approx-0.38832…

Solve for y: (y-1)(y-2)= 1/(2y^2)

The solution is y\approx 2.10257…,y\approx-0.38832…

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(y - 1) (y - 2) = \frac{1}{2 y ^{2}}

y \approx 2.10257 \dots, y \approx - 0.38832 \dots

Solution steps

(y - 1) (y - 2) = \frac{1}{2 y ^{2}}

Multiply both sides by

y^{2}

(y - 1) (y - 2) y^{2} = \frac{1}{2}

Solve

(y - 1) (y - 2) y^{2} = \frac{1}{2} : y \approx 2.10257 \dots, y \approx - 0.38832 \dots

y \approx 2.10257 \dots, y \approx - 0.38832 \dots

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y \approx 2.10257 \dots, y \approx - 0.38832 \dots

\frac{a x + b}{c x + d} = 9

\frac{a x + b}{c x + d} = 8

\frac{15}{2 x} + \frac{7}{x} = 1

\frac{∣ x - 2 ∣}{x + 1} = 5

x^{- 1} = - 3

What is the answer to (y-1)(y-2)= 1/(2y^2) ?
The answer to (y-1)(y-2)= 1/(2y^2) is y\approx 2.10257…,y\approx-0.38832…
Solve for y: (y-1)(y-2)= 1/(2y^2)
The solution is y\approx 2.10257…,y\approx-0.38832…