What is the answer to t/(t+1)=(t+1)/3 ?

The answer to t/(t+1)=(t+1)/3 is t= 1/2+i(sqrt(3))/2 ,t= 1/2-i(sqrt(3))/2

Solve for t: t/(t+1)=(t+1)/3

The solution is t= 1/2+i(sqrt(3))/2 ,t= 1/2-i(sqrt(3))/2

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\frac{t}{t + 1} = \frac{t + 1}{3}

t = \frac{1}{2} + i \frac{3}{2}, t = \frac{1}{2} - i \frac{3}{2}

Solution steps

\frac{t}{t + 1} = \frac{t + 1}{3}

Cross multiply

t \cdot 3 = (t + 1)^{2}

Solve

t \cdot 3 = (t + 1)^{2} : t = \frac{1}{2} + i \frac{3}{2}, t = \frac{1}{2} - i \frac{3}{2}

t = \frac{1}{2} + i \frac{3}{2}, t = \frac{1}{2} - i \frac{3}{2}

y, x = \frac{y}{y - 2}

y, x = \frac{y}{y - 1}

\frac{x}{2 x + 1} = \frac{3}{5}

\frac{9}{x - 3} + 2 = \frac{3 x}{x - 3}

\frac{20}{x} = \frac{15}{13.5}

What is the answer to t/(t+1)=(t+1)/3 ?
The answer to t/(t+1)=(t+1)/3 is t= 1/2+i(sqrt(3))/2 ,t= 1/2-i(sqrt(3))/2
Solve for t: t/(t+1)=(t+1)/3
The solution is t= 1/2+i(sqrt(3))/2 ,t= 1/2-i(sqrt(3))/2