What is the answer to (x-2}{x+1}=\frac{-8)/x ?

The answer to (x-2}{x+1}=\frac{-8)/x is x=-2,x=-4

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(x-2}{x+1}=\frac{-8)/x

\frac{x - 2}{x + 1} = \frac{- 8}{x}

x = - 2, x = - 4

Solution steps

\frac{x - 2}{x + 1} = \frac{- 8}{x}

Cross multiply

(x - 2) x = - (x + 1) \cdot 8

Solve

(x - 2) x = - (x + 1) \cdot 8 : x = - 2, x = - 4

x = - 2, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Combine undefined points with solutions:

x = - 2, x = - 4

(x + \frac{1}{x})^{2} = 2

H, M A = \frac{8 T}{9 H}

(\frac{90}{x} + 2) (x - 5) = 90

6 - \frac{5}{z} = \frac{25}{z}

\frac{7}{x - 9} = \frac{3}{4 - x}

What is the answer to (x-2}{x+1}=\frac{-8)/x ?
The answer to (x-2}{x+1}=\frac{-8)/x is x=-2,x=-4
Solve for x: (x-2}{x+1}=\frac{-8)/x
The solution is x=-2,x=-4