What is the answer to solvefor d,(ab)/d+c=e ?

The answer to solvefor d,(ab)/d+c=e is d=(ab)/(e-c);\quad c\ne e

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solvefor d,(ab)/d+c=e

solve for

d, \frac{ab}{d} + c = e

d = \frac{ab}{e - c}; c \neq = e

Solution steps

\frac{ab}{d} + c = e

Move

c

to the right side

\frac{ab}{d} = e - c

Multiply both sides by

d

ab = e d - c d

Switch sides

e d - c d = ab

Factor

e d - c d : d (e - c)

d (e - c) = ab

Divide both sides by

e - c; c \neq = e

d = \frac{ab}{e - c}; c \neq = e

1 + \frac{6}{y - 2} = \frac{3 y}{y - 2}

\frac{3}{x + 2} = \frac{x}{x + 1}

\frac{x + 2}{x - 1} = 2

\frac{3}{x} = \frac{2}{6}

\frac{3}{2 x} - \frac{5}{3 x} = 2

What is the answer to solvefor d,(ab)/d+c=e ?
The answer to solvefor d,(ab)/d+c=e is d=(ab)/(e-c);\quad c\ne e