What is the answer to solvefor x,x^{-2}=a ?

The answer to solvefor x,x^{-2}=a is x= 1/(sqrt(a)),x=-1/(sqrt(a));\quad a\ne 0

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solvefor x,x^{-2}=a

solve for

x, x^{- 2} = a

x = \frac{1}{a}, x = - \frac{1}{a}; a \neq = 0

Solution steps

x^{- 2} = a

Refine

\frac{1}{x ^{2}} = a

Multiply both sides by

x^{2}

1 = a x^{2}

Solve

1 = a x^{2} : x = \frac{1}{a}, x = - \frac{1}{a}; a \neq = 0

x = \frac{1}{a}, x = - \frac{1}{a}; a \neq = 0

\frac{2 x + 3}{x + 1} = \frac{5}{3}

\frac{10}{2 q + 8} = \frac{1}{10}

3 = \frac{69}{b}

\frac{x - 12}{x} = \frac{7}{20}

\frac{20}{x} = 0.714

What is the answer to solvefor x,x^{-2}=a ?
The answer to solvefor x,x^{-2}=a is x= 1/(sqrt(a)),x=-1/(sqrt(a));\quad a\ne 0