What is the answer to solvefor b,2=Q+f/b ?

The answer to solvefor b,2=Q+f/b is b= f/(2-Q);\quad Q\ne 2

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solvefor b,2=Q+f/b

solve for

b, 2 = Q + \frac{f}{b}

b = \frac{f}{2 - Q}; Q \neq = 2

Solution steps

2 = Q + \frac{f}{b}

Move

Q

to the left side

2 - Q = \frac{f}{b}

Multiply both sides by

b

2 b - Q b = f

Factor

2 b - Q b : b (2 - Q)

b (2 - Q) = f

Divide both sides by

2 - Q; Q \neq = 2

b = \frac{f}{2 - Q}; Q \neq = 2

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y, x = \frac{y + 2}{2 y + 1}

\frac{1}{x + 2} + 4 = \frac{13}{x + 2}

0.64 = \frac{x ^{2}}{( 0.1 - x ) ^{2}}

What is the answer to solvefor b,2=Q+f/b ?
The answer to solvefor b,2=Q+f/b is b= f/(2-Q);\quad Q\ne 2