What is the answer to (x^2+x-20)/(x-4)=x+5 ?

The answer to (x^2+x-20)/(x-4)=x+5 is x\ne 4

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(x^2+x-20)/(x-4)=x+5

\frac{x ^{2} + x - 20}{x - 4} = x + 5

x \neq = 4

Solution steps

\frac{x ^{2} + x - 20}{x - 4} = x + 5

Simplify

\frac{x ^{2} + x - 20}{x - 4} : x + 5

x + 5 = x + 5

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 4

Since the equation is undefined for:

4

x \neq = 4

\frac{2}{5} + \frac{2}{x} = 1

- \frac{3}{25} = \frac{15}{x}

\frac{9}{5} = \frac{w + 21}{w + 5}

a, u = \frac{v + w}{a - k}

\frac{1}{x - 1} + 5 = \frac{21}{x - 1}

What is the answer to (x^2+x-20)/(x-4)=x+5 ?
The answer to (x^2+x-20)/(x-4)=x+5 is x\ne 4
Solve for x: (x^2+x-20)/(x-4)=x+5
The solution is x\ne 4