What is the answer to (z^2-2z-4)/z =1 ?

The answer to (z^2-2z-4)/z =1 is z=4,z=-1

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(z^2-2z-4)/z =1

\frac{z ^{2} - 2 z - 4}{z} = 1

z = 4, z = - 1

Solution steps

\frac{z ^{2} - 2 z - 4}{z} = 1

Multiply both sides by

z

z^{2} - 2 z - 4 = z

Solve

z^{2} - 2 z - 4 = z : z = 4, z = - 1

z = 4, z = - 1

Verify Solutions

Find undefined (singularity) points:

z = 0

Combine undefined points with solutions:

z = 4, z = - 1

- \frac{6}{x + 1} + 6 = \frac{1}{x}

\frac{x - 6}{4 x} + 1 = \frac{x + 3}{x}

\frac{16}{x ^{2}} = \frac{50}{4}

\frac{4}{x} = \frac{5}{12 - x}

\frac{4}{x} = x

What is the answer to (z^2-2z-4)/z =1 ?
The answer to (z^2-2z-4)/z =1 is z=4,z=-1
Solve for z: (z^2-2z-4)/z =1
The solution is z=4,z=-1