What is the answer to 5=(2x^2-8x)/(1-x) ?

The answer to 5=(2x^2-8x)/(1-x) is x= 5/2 ,x=-1

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5=(2x^2-8x)/(1-x)

5 = \frac{2 x ^{2} - 8 x}{1 - x}

x = \frac{5}{2}, x = - 1

Decimal Notation

x = 2.5, x = - 1

Solution steps

5 = \frac{2 x ^{2} - 8 x}{1 - x}

Multiply both sides by

1 - x

5 (1 - x) = 2 x^{2} - 8 x

Solve

5 (1 - x) = 2 x^{2} - 8 x : x = \frac{5}{2}, x = - 1

x = \frac{5}{2}, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = \frac{5}{2}, x = - 1

\frac{2 x + 1}{x + 1} = \frac{3}{x + 1}

\frac{x + 4}{x - 2} = 0

x^{- 2} + 2 x^{- 1} - 3 = 0

\frac{1}{x} = \frac{3}{x - 8}

7 = \frac{40}{z} - 1

What is the answer to 5=(2x^2-8x)/(1-x) ?
The answer to 5=(2x^2-8x)/(1-x) is x= 5/2 ,x=-1
Solve for x: 5=(2x^2-8x)/(1-x)
The solution is x= 5/2 ,x=-1