What is the answer to 100=80(1+(4t)/(t^2+16)) ?

The answer to 100=80(1+(4t)/(t^2+16)) is t=4(2+sqrt(3)),t=4(2-sqrt(3))

Solve for t: 100=80(1+(4t)/(t^2+16))

The solution is t=4(2+sqrt(3)),t=4(2-sqrt(3))

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100 = 80 (1 + \frac{4 t}{t ^{2} + 16})

t = 4 (2 + 3), t = 4 (2 - 3)

Decimal Notation

t = 14.92820 \dots, t = 1.07179 \dots

Solution steps

100 = 80 (1 + \frac{4 t}{t ^{2} + 16})

Expand

80 (1 + \frac{4 t}{t ^{2} + 16}) : 80 + \frac{320 t}{t ^{2} + 16}

100 = 80 + \frac{320 t}{t ^{2} + 16}

Move

80

to the left side

20 = \frac{320 t}{t ^{2} + 16}

Multiply both sides by

t^{2} + 16

20 (t^{2} + 16) = 320 t

Solve

20 (t^{2} + 16) = 320 t : t = 4 (2 + 3), t = 4 (2 - 3)

t = 4 (2 + 3), t = 4 (2 - 3)

b^{- 2} = \frac{1}{4}

\frac{3}{4 x - 5} = x

\frac{x}{3 x + 4} = 5

2 = \frac{2}{3} - \frac{7}{y}

y - \frac{1}{y} = \frac{3 y}{4}

What is the answer to 100=80(1+(4t)/(t^2+16)) ?
The answer to 100=80(1+(4t)/(t^2+16)) is t=4(2+sqrt(3)),t=4(2-sqrt(3))
Solve for t: 100=80(1+(4t)/(t^2+16))
The solution is t=4(2+sqrt(3)),t=4(2-sqrt(3))