What is the answer to n/(3n+2)+1= 4/(n-2) ?

The answer to n/(3n+2)+1= 4/(n-2) is n=(9+sqrt(129))/4 ,n=(9-sqrt(129))/4

Solve for n: n/(3n+2)+1= 4/(n-2)

The solution is n=(9+sqrt(129))/4 ,n=(9-sqrt(129))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{n}{3 n + 2} + 1 = \frac{4}{n - 2}

n = \frac{9 + 129}{4}, n = \frac{9 - 129}{4}

Decimal Notation

n = 5.08945 \dots, n = - 0.58945 \dots

Solution steps

\frac{n}{3 n + 2} + 1 = \frac{4}{n - 2}

Multiply by LCM

n (n - 2) + (n - 2) (3 n + 2) = 4 (3 n + 2)

Solve

n (n - 2) + (n - 2) (3 n + 2) = 4 (3 n + 2) : n = \frac{9 + 129}{4}, n = \frac{9 - 129}{4}

n = \frac{9 + 129}{4}, n = \frac{9 - 129}{4}

Verify Solutions

Find undefined (singularity) points:

n = - \frac{2}{3}, n = 2

Combine undefined points with solutions:

n = \frac{9 + 129}{4}, n = \frac{9 - 129}{4}

\frac{30}{23} = \frac{120}{c}

\frac{2 x}{x - 1} - 2 = \frac{x - 1}{x}

28 x - 33 = \frac{28}{x}

\frac{x}{x + 1} = \frac{x}{x - 3}

2 = \frac{9}{s - 5}

What is the answer to n/(3n+2)+1= 4/(n-2) ?
The answer to n/(3n+2)+1= 4/(n-2) is n=(9+sqrt(129))/4 ,n=(9-sqrt(129))/4
Solve for n: n/(3n+2)+1= 4/(n-2)
The solution is n=(9+sqrt(129))/4 ,n=(9-sqrt(129))/4