What is the answer to solvefor y,y^{-1}=x ?

The answer to solvefor y,y^{-1}=x is y= 1/x ;\quad x\ne 0

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solvefor y,y^{-1}=x

solve for

y, y^{- 1} = x

y = \frac{1}{x}; x \neq = 0

Solution steps

y^{- 1} = x

Refine

\frac{1}{y} = x

Multiply both sides by

y

1 = x y

Switch sides

x y = 1

Divide both sides by

x; x \neq = 0

y = \frac{1}{x}; x \neq = 0

\frac{2 x}{x - 2} = \frac{- 4}{2 - x}

0 = \frac{- 9 x}{x ^{2} + 1}

\frac{2 y}{2 y + 5} - \frac{1}{3} = - 1

5 x^{- 2} - 24 x^{- 1} - 5 = 0

\frac{x}{x - 4} = \frac{4}{x - 4} + 4

What is the answer to solvefor y,y^{-1}=x ?
The answer to solvefor y,y^{-1}=x is y= 1/x ;\quad x\ne 0