What is the answer to (6/y)^2+y^2=13 ?

The answer to (6/y)^2+y^2=13 is y=3,y=-3,y=2,y=-2

Solve for y: (6/y)^2+y^2=13

The solution is y=3,y=-3,y=2,y=-2

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(\frac{6}{y})^{2} + y^{2} = 13

y = 3, y = - 3, y = 2, y = - 2

Solution steps

(\frac{6}{y})^{2} + y^{2} = 13

Simplify

(\frac{6}{y})^{2} : \frac{36}{y ^{2}}

\frac{36}{y ^{2}} + y^{2} = 13

Multiply both sides by

y^{2}

36 + y^{4} = 13 y^{2}

Solve

36 + y^{4} = 13 y^{2} : y = 3, y = - 3, y = 2, y = - 2

y = 3, y = - 3, y = 2, y = - 2

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = 3, y = - 3, y = 2, y = - 2

\frac{1}{x} + 3 = 0

\frac{2 x}{x + 4} = 5 - \frac{8}{x + 4}

\frac{10}{2 a} = \frac{20}{4}

\frac{5 ( 2 x + 1 ) ^{2}}{4 x + 5} = 5 x - 1

\frac{2}{x - 2} = \frac{5}{x + 3}

What is the answer to (6/y)^2+y^2=13 ?
The answer to (6/y)^2+y^2=13 is y=3,y=-3,y=2,y=-2
Solve for y: (6/y)^2+y^2=13
The solution is y=3,y=-3,y=2,y=-2