What is the answer to ((2x-3)(x+5))/(x-7)=0 ?

The answer to ((2x-3)(x+5))/(x-7)=0 is x= 3/2 ,x=-5

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((2x-3)(x+5))/(x-7)=0

\frac{( 2 x - 3 ) ( x + 5 )}{x - 7} = 0

x = \frac{3}{2}, x = - 5

Solution steps

\frac{( 2 x - 3 ) ( x + 5 )}{x - 7} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

(2 x - 3) (x + 5) = 0

Solve

(2 x - 3) (x + 5) = 0 : x = \frac{3}{2}, x = - 5

x = \frac{3}{2}, x = - 5

Verify Solutions

Find undefined (singularity) points:

x = 7

Combine undefined points with solutions:

x = \frac{3}{2}, x = - 5

\frac{x + 2}{x} = \frac{3}{5}

4 + \frac{6}{x} = \frac{5}{2}

\frac{5}{x} + 3 = \frac{4}{x - 1}

\frac{1}{x} + \frac{3}{x} = 4

3 x - \frac{2}{x} = 5

What is the answer to ((2x-3)(x+5))/(x-7)=0 ?
The answer to ((2x-3)(x+5))/(x-7)=0 is x= 3/2 ,x=-5
Solve for x: ((2x-3)(x+5))/(x-7)=0
The solution is x= 3/2 ,x=-5