What is the answer to 16x^{-4}-17x^{-2}+1=0 ?

The answer to 16x^{-4}-17x^{-2}+1=0 is x=4,x=-4,x=1,x=-1

Solve for x: 16x^{-4}-17x^{-2}+1=0

The solution is x=4,x=-4,x=1,x=-1

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16 x^{- 4} - 17 x^{- 2} + 1 = 0

x = 4, x = - 4, x = 1, x = - 1

Solution steps

16 x^{- 4} - 17 x^{- 2} + 1 = 0

Refine

\frac{16}{x ^{4}} - \frac{17}{x ^{2}} + 1 = 0

Multiply by LCM

16 - 17 x^{2} + x^{4} = 0

Solve

16 - 17 x^{2} + x^{4} = 0 : x = 4, x = - 4, x = 1, x = - 1

x = 4, x = - 4, x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 4, x = - 4, x = 1, x = - 1

\frac{7}{x} = \frac{20}{5}

\frac{x}{x + 4} + 1 = \frac{16}{x + 4}

\frac{2}{x} = (1.2)

\frac{1}{x + 1} = 2

\frac{y + 4}{2 y - 3} = \frac{3}{5}

What is the answer to 16x^{-4}-17x^{-2}+1=0 ?
The answer to 16x^{-4}-17x^{-2}+1=0 is x=4,x=-4,x=1,x=-1
Solve for x: 16x^{-4}-17x^{-2}+1=0
The solution is x=4,x=-4,x=1,x=-1