What is the answer to (-12x+20)/((x+3)(x-4))=0 ?

The answer to (-12x+20)/((x+3)(x-4))=0 is x= 5/3

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(-12x+20)/((x+3)(x-4))=0

\frac{- 12 x + 20}{( x + 3 ) ( x - 4 )} = 0

x = \frac{5}{3}

Decimal Notation

x = 1.66666 \dots

Solution steps

\frac{- 12 x + 20}{( x + 3 ) ( x - 4 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 12 x + 20 = 0

Move

20

to the right side

- 12 x = - 20

Divide both sides by

- 12

x = \frac{5}{3}

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = 4

Combine undefined points with solutions:

x = \frac{5}{3}

\frac{2}{x - 1} - \frac{6}{2 x + 1} = 5

7 - \frac{2}{x} = 4 + \frac{10}{x}

\frac{x}{x + 3} + \frac{5}{x + 4} = 0

6 - \frac{1}{x} = \frac{1}{x ^{2}}

\frac{x}{2 - x} = \frac{1}{x}

What is the answer to (-12x+20)/((x+3)(x-4))=0 ?
The answer to (-12x+20)/((x+3)(x-4))=0 is x= 5/3
Solve for x: (-12x+20)/((x+3)(x-4))=0
The solution is x= 5/3