What are the solutions to the equation 4-x^2=0 ?

The solutions to the equation 4-x^2=0 are x=2,x=-2

Find the zeros of 4-x^2=0

The zeros of 4-x^2=0 are x=2,x=-2

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4 - x^{2} = 0

x = 2, x = - 2

Solution steps

4 - x^{2} = 0

Move

4

to the right side

- x^{2} = - 4

Divide both sides by

- 1

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x, VV - 2 \cdot G \cdot R - K V \frac{V}{M} = x^{2} - K \cdot \frac{x ^{2}}{M} - 2 \cdot K V \frac{x}{M}

(\frac{81}{16})^{\frac{1}{4}}

4 x^{2} + 12 x - 15 = 0

c^{3} - 8

7 x = \frac{14 + 7 x}{2}

What are the solutions to the equation 4-x^2=0 ?
The solutions to the equation 4-x^2=0 are x=2,x=-2
Find the zeros of 4-x^2=0
The zeros of 4-x^2=0 are x=2,x=-2