What are the solutions to the equation 6z^2+7z+3=0 ?

The solutions to the equation 6z^2+7z+3=0 are z=-7/12+i(sqrt(23))/(12),z=-7/12-i(sqrt(23))/(12)

Find the zeros of 6z^2+7z+3=0

The zeros of 6z^2+7z+3=0 are z=-7/12+i(sqrt(23))/(12),z=-7/12-i(sqrt(23))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 z^{2} + 7 z + 3 = 0

z = - \frac{7}{12} + i \frac{23}{12}, z = - \frac{7}{12} - i \frac{23}{12}

Solution steps

6 z^{2} + 7 z + 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

7^{2} - 4 \cdot 6 \cdot 3 : 23 i

z_{1, 2} = \frac{- 7 \pm 23 i}{2 \cdot 6}

Separate the solutions

z_{1} = \frac{- 7 + 23 i}{2 \cdot 6}, z_{2} = \frac{- 7 - 23 i}{2 \cdot 6}

z = \frac{- 7 + 23 i}{2 \cdot 6} : - \frac{7}{12} + i \frac{23}{12}

z = \frac{- 7 - 23 i}{2 \cdot 6} : - \frac{7}{12} - i \frac{23}{12}

The solutions to the quadratic equation are:

z = - \frac{7}{12} + i \frac{23}{12}, z = - \frac{7}{12} - i \frac{23}{12}

- 3 x - 8 = 7 x + 10

- 7 x - 4 x = 10 x + 8 - 11

4 v^{2} r - 25 v r + 25 r

(72)^{2}

25 s^{2} - 30 s + 9

What are the solutions to the equation 6z^2+7z+3=0 ?
The solutions to the equation 6z^2+7z+3=0 are z=-7/12+i(sqrt(23))/(12),z=-7/12-i(sqrt(23))/(12)
Find the zeros of 6z^2+7z+3=0
The zeros of 6z^2+7z+3=0 are z=-7/12+i(sqrt(23))/(12),z=-7/12-i(sqrt(23))/(12)