What is the answer to ((2x-3))/((x+1))=0 ?

The answer to ((2x-3))/((x+1))=0 is x= 3/2

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((2x-3))/((x+1))=0

\frac{( 2 x - 3 )}{( x + 1 )} = 0

x = \frac{3}{2}

Solution steps

\frac{( 2 x - 3 )}{( x + 1 )} = 0

Simplify

\frac{( 2 x - 3 )}{( x + 1 )} : \frac{2 x - 3}{x + 1}

\frac{2 x - 3}{x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x - 3 = 0

Move

3

to the right side

2 x = 3

Divide both sides by

2

x = \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = \frac{3}{2}

\frac{x}{x - 2} = 1

\frac{x}{x - 2} = 4

\frac{x}{x - 2} = 6

\frac{6}{4} = \frac{3}{x}

\frac{x + 1}{x} = 1 + \frac{1}{x}

What is the answer to ((2x-3))/((x+1))=0 ?
The answer to ((2x-3))/((x+1))=0 is x= 3/2
Solve for x: ((2x-3))/((x+1))=0
The solution is x= 3/2