What is the answer to 3x^{-2}-17x^{-1}+20=0 ?

The answer to 3x^{-2}-17x^{-1}+20=0 is x= 3/5 ,x= 1/4

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3x^{-2}-17x^{-1}+20=0

3 x^{- 2} - 17 x^{- 1} + 20 = 0

x = \frac{3}{5}, x = \frac{1}{4}

Solution steps

3 x^{- 2} - 17 x^{- 1} + 20 = 0

Refine

\frac{3}{x ^{2}} - \frac{17}{x} + 20 = 0

Multiply by LCM

3 - 17 x + 20 x^{2} = 0

Solve

3 - 17 x + 20 x^{2} = 0 : x = \frac{3}{5}, x = \frac{1}{4}

x = \frac{3}{5}, x = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{3}{5}, x = \frac{1}{4}

\frac{5}{11} = \frac{2}{x}

s = \frac{d}{t}, t

\frac{9}{4 x} - \frac{7}{4} = - 4

\frac{2}{x - 1} = \frac{3}{x + 1}

\frac{x ^{2}}{x - 1} = 4

What is the answer to 3x^{-2}-17x^{-1}+20=0 ?
The answer to 3x^{-2}-17x^{-1}+20=0 is x= 3/5 ,x= 1/4
Solve for x: 3x^{-2}-17x^{-1}+20=0
The solution is x= 3/5 ,x= 1/4