What is the answer to 2-(y-8)^{-1}=6(y-8)^{-2} ?

The answer to 2-(y-8)^{-1}=6(y-8)^{-2} is y=10,y= 13/2

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2-(y-8)^{-1}=6(y-8)^{-2}

2 - (y - 8)^{- 1} = 6 (y - 8)^{- 2}

y = 10, y = \frac{13}{2}

Solution steps

2 - (y - 8)^{- 1} = 6 (y - 8)^{- 2}

Refine

2 - \frac{1}{y - 8} = \frac{6}{( y - 8 ) ^{2}}

Multiply by LCM

2 (y - 8)^{2} - (y - 8) = 6

Solve

2 (y - 8)^{2} - (y - 8) = 6 : y = 10, y = \frac{13}{2}

y = 10, y = \frac{13}{2}

Verify Solutions

Find undefined (singularity) points:

y = 8

Combine undefined points with solutions:

y = 10, y = \frac{13}{2}

\frac{1}{x ^{4}} = 16

y, x = 4 - \frac{1}{y}

\frac{x}{x - 1} + \frac{1}{x} = 1

\frac{2}{3} - \frac{x - 6}{x - 5} = 0

\frac{3}{x + 1} = 2

What is the answer to 2-(y-8)^{-1}=6(y-8)^{-2} ?
The answer to 2-(y-8)^{-1}=6(y-8)^{-2} is y=10,y= 13/2
Solve for y: 2-(y-8)^{-1}=6(y-8)^{-2}
The solution is y=10,y= 13/2