What is the answer to (t)=(5t)/(t^2+1) ?

The answer to (t)=(5t)/(t^2+1) is t=0,t=-2,t=2

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(t)=(5t)/(t^2+1)

(t) = \frac{5 t}{t ^{2} + 1}

t = 0, t = - 2, t = 2

Solution steps

(t) = \frac{5 t}{t ^{2} + 1}

Multiply both sides by

t^{2} + 1

t (t^{2} + 1) = 5 t

Solve

t (t^{2} + 1) = 5 t : t = 0, t = - 2, t = 2

t = 0, t = - 2, t = 2

\frac{280}{q + 2} = 20 + 2.5 q

2 x - \frac{9}{x} = 3

\frac{( 0.8 - 0.3 x )}{x} = 0

\frac{3}{2} = \frac{- 7 x + 9}{3 x}

\frac{8}{10} = \frac{12}{x}

What is the answer to (t)=(5t)/(t^2+1) ?
The answer to (t)=(5t)/(t^2+1) is t=0,t=-2,t=2
Solve for t: (t)=(5t)/(t^2+1)
The solution is t=0,t=-2,t=2