What is the answer to (2x^2+9x-5)/(x^4+1)=0 ?

The answer to (2x^2+9x-5)/(x^4+1)=0 is x= 1/2 ,x=-5

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(2x^2+9x-5)/(x^4+1)=0

\frac{2 x ^{2} + 9 x - 5}{x ^{4} + 1} = 0

x = \frac{1}{2}, x = - 5

Decimal Notation

x = 0.5, x = - 5

Solution steps

\frac{2 x ^{2} + 9 x - 5}{x ^{4} + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x^{2} + 9 x - 5 = 0

Solve

2 x^{2} + 9 x - 5 = 0 : x = \frac{1}{2}, x = - 5

x = \frac{1}{2}, x = - 5

\frac{- 5}{x - 5} + \frac{2}{x + 9} = 1

\frac{10}{2} = \frac{100}{r}

\frac{5 x}{x + 1} = 2 - \frac{5}{x + 1}

\frac{x + 3}{x - 7} = \frac{- 2}{x}

f^{- 1} (3) = 1, f (1)

What is the answer to (2x^2+9x-5)/(x^4+1)=0 ?
The answer to (2x^2+9x-5)/(x^4+1)=0 is x= 1/2 ,x=-5
Solve for x: (2x^2+9x-5)/(x^4+1)=0
The solution is x= 1/2 ,x=-5