What is the answer to solvefor x,y+2/(x^2)=0 ?

The answer to solvefor x,y+2/(x^2)=0 is x=isqrt(2/y),x=-isqrt(2/y);\quad y\ne 0

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solvefor x,y+2/(x^2)=0

solve for

x, y + \frac{2}{x ^{2}} = 0

x = i \frac{2}{y}, x = - i \frac{2}{y}; y \neq = 0

Solution steps

y + \frac{2}{x ^{2}} = 0

Multiply both sides by

x^{2}

y x^{2} + 2 = 0

Solve

y x^{2} + 2 = 0 : x = i \frac{2}{y}, x = - i \frac{2}{y}; y \neq = 0

x = i \frac{2}{y}, x = - i \frac{2}{y}; y \neq = 0

t (t) = 1 - \frac{4}{t ^{2}}

\frac{10}{4} = \frac{4}{3 p}

\frac{4}{x} - \frac{1}{x - 1} = 1

x, \frac{2 a}{x - 1} = a - b

125 - \frac{9000}{x ^{2}} = 0

What is the answer to solvefor x,y+2/(x^2)=0 ?
The answer to solvefor x,y+2/(x^2)=0 is x=isqrt(2/y),x=-isqrt(2/y);\quad y\ne 0