What is the answer to 1/((x+3)(x+3))=1,x\ne-3 ?

The answer to 1/((x+3)(x+3))=1,x\ne-3 is x=-2,x=-4

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1/((x+3)(x+3))=1,x\ne-3

\frac{1}{( x + 3 ) ( x + 3 )} = 1, x \neq = - 3

x = - 2, x = - 4

Solution steps

\frac{1}{( x + 3 ) ( x + 3 )} = 1

Simplify

\frac{1}{( x + 3 ) ( x + 3 )} : \frac{1}{( x + 3 ) ^{2}}

\frac{1}{( x + 3 ) ^{2}} = 1

Multiply both sides by

(x + 3)^{2}

1 = (x + 3)^{2}

Solve

1 = (x + 3)^{2} : x = - 2, x = - 4

x = - 2, x = - 4

Verify Solutions

Find undefined (singularity) points:

x = - 3

Combine undefined points with solutions:

x = - 2, x = - 4

Check constrains

x = - 2, x = - 4

1332 = \frac{10}{v}

\frac{2}{\frac{x}{2 - x} - 5} = 0

5 = \frac{2}{x}

\frac{m}{a} = \frac{n}{p}

0.1 = \frac{0.4 \cdot V}{355 + V}

What is the answer to 1/((x+3)(x+3))=1,x\ne-3 ?
The answer to 1/((x+3)(x+3))=1,x\ne-3 is x=-2,x=-4
Solve for x: 1/((x+3)(x+3))=1,x\ne-3
The solution is x=-2,x=-4