What is the answer to solvefor y,y^{-2}=x-1 ?

The answer to solvefor y,y^{-2}=x-1 is y= 1/(sqrt(x-1)),y=-1/(sqrt(x-1));\quad x\ne 1

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solvefor y,y^{-2}=x-1

solve for

y, y^{- 2} = x - 1

y = \frac{1}{x - 1}, y = - \frac{1}{x - 1}; x \neq = 1

Solution steps

y^{- 2} = x - 1

Refine

\frac{1}{y ^{2}} = x - 1

Multiply both sides by

y^{2}

1 = x y^{2} - y^{2}

Solve

1 = x y^{2} - y^{2} : y = \frac{1}{x - 1}, y = - \frac{1}{x - 1}; x \neq = 1

y = \frac{1}{x - 1}, y = - \frac{1}{x - 1}; x \neq = 1

z - 4 = 5 z^{- 1}

a = \frac{2 d}{t ^{2}}

1000 = \frac{1}{x ^{2} - 1}

\frac{360}{40 + A} = \frac{6}{1}

\frac{6 x ^{3} - 1}{2 x ^{2} + x - 1} = 0

What is the answer to solvefor y,y^{-2}=x-1 ?
The answer to solvefor y,y^{-2}=x-1 is y= 1/(sqrt(x-1)),y=-1/(sqrt(x-1));\quad x\ne 1