What is the answer to x^{-2}-2x^{-1}-35=0 ?

The answer to x^{-2}-2x^{-1}-35=0 is x=-1/5 ,x= 1/7

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x^{-2}-2x^{-1}-35=0

x^{- 2} - 2 x^{- 1} - 35 = 0

x = - \frac{1}{5}, x = \frac{1}{7}

Decimal Notation

x = - 0.2, x = 0.14285 \dots

Solution steps

x^{- 2} - 2 x^{- 1} - 35 = 0

Refine

\frac{1}{x ^{2}} - \frac{2}{x} - 35 = 0

Multiply by LCM

1 - 2 x - 35 x^{2} = 0

Solve

1 - 2 x - 35 x^{2} = 0 : x = - \frac{1}{5}, x = \frac{1}{7}

x = - \frac{1}{5}, x = \frac{1}{7}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{1}{5}, x = \frac{1}{7}

x \frac{x + 5}{x} = \frac{4}{5}

\frac{9}{x} = 11

\frac{6}{3 x - 1} = \frac{2 x - 7}{7}

\frac{x - 1}{x + 1} = \frac{5}{3}

\frac{5}{3} = \frac{40}{x}

What is the answer to x^{-2}-2x^{-1}-35=0 ?
The answer to x^{-2}-2x^{-1}-35=0 is x=-1/5 ,x= 1/7
Solve for x: x^{-2}-2x^{-1}-35=0
The solution is x=-1/5 ,x= 1/7